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Relations



Chapter 1  Relations (section 4.1, 4.2 and 4.4)

1.1  Introduction

A mere set of words would not make a good dictionary.

It would be a pain to find a particular word!

A usable dictionary has some structure: the words are sorted.

In general, the more structure a set have, the more useful it is.

A way to bring structure into this set is to describe the relations between its elements, or between its elements and the elements of another set.

In this section we will see how we can formalize and study relations.
Exemple 1   Imagine you want to build a house.

Figure
1.1 shows the tasks that need to be completed.


Figure 1.1: Tasks to build a house


Let S:={ F,W,E,I,O,R} be the set of all tasks.

Problem: can we do the tasks in any order ?

For example, it would be better to build the walls AFTER the foundations!

S in itself does not contain enough information to choose a correct order.


Figure 1.2: Constraints between the tasks to build a house


Set of constraints: rho:={(F,W),(W,O),(W,E),(R,E),(R,I)}.

This set of constraints gives some structure to S, and makes it useful.

1.2  Relations

1.2.1  Definitions


Définition 1   A binary relation on a set S is a subset rho of S× S.

Let x and y be two elements of S.

Then x is
in relation with y (denoted x rho y) iff (x,y)inrho.
Exemple 2   Let rho be the relation ``is a prerequisite for'':
rho:={(F,W),(W,O),(W,E),(R,E),(R,I)}

Then, (F,W)inrho, but (I,O)not inrho.

So, F
rho W is true, whereas I rho O is false.
A relation can be defined by a property.
Exercice 1   Let S:={1,2,3,4,5}. Draw the relations defined by:
  1. x rho1 y iff x=y;
  2. x rho2 y iff x<= y;
  3. x rho3 y iff x divides y;
  4. x rho4 y iff x-y is even.
Définition 2   A binary relation between two sets S and T is a subset rho of S× T.

A
n-ary relation between n sets S1,...,Sn is a subset rho of S1×···× Sn.
Exemple 3   Let M be a set of male and F a set of female students.

We can define the relation ``is married to''.

1.2.2  Basic properties of relations

Is there anything particular about the relation ``is married to'' ?
Définition 3   Let rho be a relation between S and T.









Exemple 4   Is x lower or equal to itself ?
Définition 4   A relation rho on a set S is reflexive iff
(for all xin S) x rho x.


Exemple 5   Assume x is equal to y. Is y equal to x ?
Définition 5   A relation rho on a set S is symmetric iff
(for all xin S)(for all yin S) (x rho y)<->(y rho x).


Exemple 6   Assume x<= y and y<= x. What can you say about x and y?
Définition 6   A relation rho on a set S is antisymmetric iff
(for all xin S)(for all yin S)[(x rho y) and (y rho x)]->(x=y).


Exemple 7   Assume x<y and y<z. What can you say about x and z?
Définition 7   A relation rho on a set S is transitive iff
(for all xin S)(for all yin S)(for all zin S)[(x rho y) and (y rho z)]->(x rho z).


Exemple 8   What are the properties of the following relations
  1. <, <=, =;
  2. ``is married to'';
  3. ``is a friend of'';
  4. ``has the same color than''.

1.2.3  Operations on relations

A relation is basically a set. So, we can use all usual set operations on relations.
Remarque 1   Let S and T be two sets.

The powerset (S× T) is the set of all binary relations between S and T.
Définition 8   Let rho and sigma be two relations between S and T.

We can construct the following new relations:
Exemple 9   Let S:=N.
  1. What is the union of <and =?
  2. What is the intersection of < and >?
  3. What is the union of < and >?
  4. Is <a sub relation of <= ?

1.2.4  Closure of a relation


Exemple 10   Lets come back to the example of the house building.


Figure 1.1: Constraints between the tasks to build a house


Do you have to do the electricity after the foundations ?

Foundations is not a direct prerequisite for electricity.

However, it still needs to be done before electricity.

The relation ``has to be done before'' is transitive, and contains the relation

``is a prerequisite for''. It's the
transitive closure of ``is a prerequisite for''.
Définition 9   Let rho be a relation.

The
transitive closure of rho is the smallest transitive relation rho*containing rho.
Exercice 2   Draw the transitive closure of ``is a prerequisite for''.
Problem 1   Is there an algorithm for computing the transivite relation of a relation?

Algorithme 2   Construction of the transitive closure rho*.
  1. rho*:=rho;
  2. Find x, y, z such that (x rho*y), (y rho*z), and (x ¬ rho*z);
  3. If no such triple exists, rho*is transitive; Exit;
  4. rho*:=rho*union{(x,z)};
  5. Repeat at step 2.
Remarque 2   The order in which you add the pairs to rho is irrelevant.
Exemple 11   Draw the relation ``has to be done before'' (Figure 1.1).
Définition 10   Let rho be a relation.

The
reflexive closure of rho is the smallest reflexive relation containing rho.

The
symmetric closure of rho is the smallest symmetric relation containing rho.
Exercice 3   Consider the following relation:



  1. Draw its reflexive closure
  2. Draw its symmetric closure
  3. Draw its transitive closure
  4. Draw its antisymmetric closure

Remarque 3   The antisymmetric closure of a relation cannot be uniquely defined!

1.3  Equivalence relations


Exemple 12   Consider a set of cars, and the relation ``has the same color as''.

What are the properties of this relation?
Définition 11   An equivalence relation is a relation which is
  1. Reflexive
  2. Symmetric
  3. Transitive

Définition 12   Let rho be a relation on a set S, and x be an element of S.

The
equivalence class of x is the set [x]of all elements y such that x rho y.
Exemple 13   The equivalence class of a car is the set of all cars having same color.
Remarque 4   If x rho y, then [x]=[y].
Exemple 14   Consider the relation same as3 on N defined by xsame as3y iff 3 divides x-y.

(we also say that x and y are
congruent modulo 3: xsame as y (mod 3))

What are the equivalence classes?
Définition 13   A partition of a set S is a collection of subsets { A1,...,Ak} of S such that:
  1. A1union···union Ak=S
  2. Aiintersect Aj for any i, j.
Exemple 15   Consider a set S of car, whose color are either red, blue, or green.

Define the following subsets of S:

R (red cars), B (blue cars), and G (green cars) .

Then, { R,B,G} is a partition of S.
The equivalence relation ``has the same color'' and the partition of the cars by color are closely related.
Théorème 1   In general:
  1. An equivalence relation on S defines a unique partition of S.
  2. A partition of S defines a unique equivalence relation on S.

Proof. Left as exercise:
  1. Construct the collection { A1,...,Ak}, and prove it is indeed a partition of S.
  2. Construct the relation rho, and prove it's indeed an equivalence relation.

Définition 14   Let S be a set, and rho be a relation on S.

The set of all the equivalence classes is called the
quotient of S by rho.
Remarque 5   This method is used a lot in set theory:

Construction of Z from N.

Construction of Z/nZ (integers modulo n) from Z.

Construction of Q from Z.

1.4  Partially Ordered Sets


Exemple 16   What are the properties of the relation ``has to be done before'' on the tasks to build a house ?
Définition 15   A partially ordered set (or poset) is a set S with a relation rho which is
  1. Reflexive
  2. Antisymmetric
  3. Transitive
Exemple 17   Which of the following are posets ?
  1. ({1,2,3,4},<=);
  2. ({1,2,3,4},<);
  3. ({1,2,3,4},=);
  4. ({1,2,3,4},rho), with x rho y iff x divides y.
  5. (({1,2,3,4}),included in or equal to).

1.4.1  Drawing posets; Hasse diagrams


Définition 16   Some names:

Définition 17   The Hasse diagram of a poset is a drawing of this poset such that:
Exemple 18   Draw all posets on 1, 2, 3, 4 indistinct nodes.

How many such posets are there on 10 nodes ?

1.4.2  Scheduling

Scheduling a set of tasks consist in allocating tasks to resources, subject to certain constraints.
Exemple 19   Consider the house building problem, with the following assumptions:


Figure 1.1: Constraints between the tasks to build a house


Schedule the tasks between 2 workers to optimize the completion time:


  Day 1 Day 2 Day 3 Day 4 Day 5 Day 6 Day 7
Worker 1              
Worker 2              



What if there is one worker ?


  Day 1 Day 2 Day 3 Day 4 Day 5 Day 6 Day 7
Worker 1              



What if there are three workers ?


  Day 1 Day 2 Day 3 Day 4 Day 5 Day 6 Day7
Worker 1              
Worker 2              
Worker 3              


Proposition 1   Consider the problem of scheduling n tasks on p processors, subject to precedence constraints, with the same assumptions and goal as above.
This is typical from scheduling problems, where a very small change in the constraints can make huge differences in the complexity of the problems.

Also, usually the complexity is as follow: Having very good scheduling algorithms is vital in industry, because a 1% difference in completion time (for example) can save thousands of dollars. Consequently, research in this topic is well financed!

1.5  Conclusion


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Relations / CSM MACS-358 / Nicolas M. Thiéry
Last modified: Fri Jan 19 13:12:20 2007